Interpreting the inequality, it is found that the correct option is given by F.
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- The first equation is of the line.
- The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.
In standard form, the equation of the line is:



Thus it is a decreasing line, which removes options J.
- We are interested in the region on the plane below the line, that is, less than the line, which removes option H.
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- As for the second equation, the normalized equation is:



- Thus, a circle centered at the origin and with radius 2.
- Now, we have to check if the line
, with coefficients
, intersects the circle, of centre 
- First, we find the following distance:

- Considering the coefficients of the line and the center of the circle.

- This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.
A similar problem is given at brainly.com/question/16505684
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>
For #4, we know V = lwh
We have the values
5184 = 2(18)h
Solve for h
5184 = 36h
144 = h.
for # 3:
we know A = pi r^2
We have
A = 3.14 * 6^2
A = 3.14 * 36
A = 113.04
for #2:
We know C = 2pi *r
C = 2(3.14)(14)
C = 28(3.14)
C = 87.92
for #1:
C = 2pi * r
C = 2(3.14)(26.3/2)
C = 2(3.14)(13.15)
C = 26.3(3.14)
C = 82.582
Answer:
1 ray is intersecting point O
Step-by-step explanation:
A ray can be defined as a part of a line that has a fixed starting point but no end point.
AD and EC both go on forever but OB has one endpoint and goes on forever.
You - 3 from 2 then do 6n=-1