Well the area of a trapezoid is defined by the following formula:
A =

where b₁ and b₂ are the bases of the trapezoid and h is the height of the trapezoid.
Let's plug in what we know into this formula:
h = 7 the perpendicular distance between the two bases
b₁ = 15 the shorter parallel side
b₂ = 25 the longer parallel side made up of 4 + 15 + 6
so, A =

This is in square units of measure of course, so 140 in²
Answer:
13 1/3 and 6 2/3.
Step-by-step explanation:
Let the 2 parts be x and (20 - x).
So x^2(20 - x) must be a maximum.
y = x^2(20 - x)
y = 20x^2 - x^3
Finding the derivative):
y' = 40x - 3x^2 = 0 for maxm/minm value.
x( 40 - 3x) = 0
40 - 3x = 0
3x = 40
x = 40/3.
This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.
So the 2 numbers are 13 1/3 and 6 2/3.
Answer:
b
Step-by-step explanation:
Answer:
f(x)^-1 = x - 4
D: {x is all real numbers}
Step-by-step explanation:
change f(x) to y
switch x with y and vice versa
solve for y
Answer:
nth term = 1 + n(13/4)
Step-by-step explanation:
3n + n/4 + 1
n = 1, 3(1) + (1)/4 + 1 = 4 + ¼ = 17/4
n = 2, 3(2) + (2)/4 + 1 = 7 + ½ = 30/4
n = 3, 3(3) + (3)/4 + 1 = 10 + ¾ = 43/4
n = 4, 3(4) + (4)/4 + 1 = 14 = 56/4
The difference between consecutive terms is 13/4
At n = 1, 17/4 = 1 + 1(13/4)
At n = 2, 30/4 = 1 + 2(13/4)
nth term = 1 + n(13/4)