<h3>4
Answers: B, C, D, and F</h3>
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Explanation:
Notice how (19)^2 = 19*19 = 361
This shows that 19 is a square root of 361. We can say ![\sqrt{361} = \sqrt{19^2} = 19](https://tex.z-dn.net/?f=%5Csqrt%7B361%7D%20%3D%20%5Csqrt%7B19%5E2%7D%20%3D%2019)
Similarly, (-19)^2 = (-19)*(-19) = 361. The two negatives cancel each other out. So that's why there are two solutions to
which are x = 19 and x = -19.
So far that accounts for answer choices B and D.
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The other two answers are
and
(choices C and F) because anything to the 1/2 power represents a square root.
![x^{1/2} = \sqrt{x}](https://tex.z-dn.net/?f=x%5E%7B1%2F2%7D%20%3D%20%5Csqrt%7Bx%7D)
anything to the 1/3 power is a cube root
![x^{1/3} = \sqrt[3]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
anything to the 1/4 power is a fourth root
![x^{1/4} = \sqrt[4]{x}](https://tex.z-dn.net/?f=x%5E%7B1%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%7D)
and so on.
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Side note: For choice C, the exponent is done first before we apply the negative. So technically we could say
for choice C to mean the same exact thing. If your teacher said
then this would not be an answer because this results in a non-real number.