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Yuki888 [10]
3 years ago
8

PPPPPPPPlease help me (20 points!!!!)

Mathematics
1 answer:
Vika [28.1K]3 years ago
4 0

\longrightarrow{\mathfrak{\frac{-9}{6}÷\frac{3}{-2}}}

\longrightarrow{\sf{\frac{-\cancel{9}}{\cancel{6}}\times\frac{-\cancel{2}}{\cancel{3}}}}

\longrightarrow{\sf{\frac{3}{3}}}

\longrightarrow{\boxed{\bf{1}}}

Identity applied -

\star{\:\:\:\:\:\:\boxed{\bf{\frac{a}{b}÷\frac{c}{d}=\frac{a}{b}\times\frac{d}{c}}}}

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Determine whether y^2 = –2x – 1 is a function.
MariettaO [177]

Answer:

It is NOT a function

Step-by-step explanation:

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Need this quick!!!
Leya [2.2K]

A function assigns the values. The correct option is graph X.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The function which is giving a constant term is the graph on the right, while the function where the value of x increases to positive infinity is the upper graph.

Hence, the correct option is graph X.

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NemiM [27]

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Step-by-step explanation:

You need to find the area of each of the shapes by multiplying the length by the width. Then, you need to add them all together. I won't do it for you because it will make it harder to learn stuff in the future but I told you the formula!!

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Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

3 0
3 years ago
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