Answer:
150 pennies were lost altogether
Step-by-step explanation:
Let the initial number of pennies owned by Dante be x pennies
Let the initial number of pennies owned by Mia be y pennies
Mathematically ;
x + y = 350 •••••••(i)
So after losing half, dante will have x/2 pennies left.
Mia lost 1/3 so she will have 2/3y left
So after all the losses, they both had equal amount of pennies
This means that;
x/2 = 2y/3
Cross multiply;
3x = 4y •••••••(ii)
Let’s solve both equations simultaneously;
From i , x = 350-y
Substitute this into equation ii
3(350-y) = 4y
1050-3y = 4y
7y = 1050
y = 1050/7
y = 150
since x = 350-y
x = 350-150 = 200
Now Dante loss x/2 = 200/2 = 100
Mia lost 1/3y = 1/3 * 150 = 50
Total pennies lost = 100 + 50 = 150
Let Y = total cost of both schools.
The total cost would be ( number of credits at Westside x 98) + (number of credits at Pinewood x 115).
The total number of credits he is taking is 14.
If w is the number of credits at Westside, then for Westside you have 98w ( $98 times the number of credit hours)
The equation is now y = 98w + (number of credits at Pinewood x 115).
The number of credit hours at Pinewood would be the total credit hours 14 minus the credit hours at Westside w, so you have 14-w, which needs to be multiplied by the cost at Pinewood.
The equation is now y = 98w + 115(14-w)
This can be simplified using the distributive property to:
Y = 98w + 1610 - 115w
Y = -17w + 1610
Answer:
A.) 
Step-by-step explanation:
f(-2) means plug in -2 in for x for the equation f(x), therefore,
f(-2) = 
Answer:
Juan travel 31.4 feet farther than Fred in one rotation.
Step-by-step explanation:
In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:
(Eq. 1)
Where:
- Radius, measured in feet.
- Angular arch, measured in radians.
- Change in linear position, measured in feet.
If both makes one rotation in the carousel, we obtain the change in linear position of each player:
Fred (
,
)



Juan (
,
)



And the difference between both travelled distances is:


Juan travel 31.4 feet farther than Fred in one rotation.