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coldgirl [10]
3 years ago
11

Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal pl

ace. If there is more than one mode, enter your answer as a comma-separated list. If an answer does not exist, enter DNE.)
Points Scored by Lynn Points scored in a basketball game Frequency
2 10
3 9
9 10
11 7
12 3
15 4
16 3
Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer: Mean = 7.8

              Median = 9

             Mode = 2,9

Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

E(X)=\frac{2(10)+3(9)+9(10)+11(7)+12(3)+15(4)+16(3)}{10+9+10+7+3+4+3}

E(X) = 7.8

Mean for the given frequency distribtuion is 7.8.

<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:

1) Find total number, n:

n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46

2) Find position, using: \frac{n+1}{2}

\frac{n+1}{2}=\frac{47}{2} = 23.5

Median is in the 23.5th position.

3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9

Median for this frequency distribution is 9.

<u>Mode</u>  is the number or value associated with the highest frequency.

In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.

Mode for this distribution is 2 and 9.

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The ________________ measures the spread of the middle 50% of the data set.
Scilla [17]

Answer:

C. interquartile range

Step-by-step explanation:

using this to show im right

"The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest."

Hope This Helped

6 0
2 years ago
Solve the triangle C = 13º, A = 22°, c = 9
guapka [62]

Answer:

thats way to much

Step-by-step explanation:

OK

7 0
3 years ago
A polygon has its vertices at the following points.
seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

\sqrt{(x2-x1)^2 + (y2 -y1)^2}

AB = \sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}

BC = |7-4| = 3

CD = \sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0
3 years ago
Consider the function f given by f(x)=x*(e^(-x^2)) for all real numbers x.
NISA [10]

Answer:

\frac{\sqrt{\pi}}{4}

Step-by-step explanation:

You are going to integrate the following function:

g(x)=x*f(x)=x*xe^{-x^2}=x^2e^{-x^2}  (1)

furthermore, you know that:

\int_0^{\infty}e^{-x^2}=\frac{\sqrt{\pi}}{2}

lets call to this integral, the integral Io.

for a general form of I you have In:

I_n=\int_0^{\infty}x^ne^{-ax^2}dx

furthermore you use the fact that:

I_n=-\frac{\partial I_{n-2}}{\partial a}

by using this last expression in an iterative way you obtain the following:

\int_0^{\infty}x^{2s}e^{-ax^2}dx=\frac{(2s-1)!!}{2^{s+1}a^s}\sqrt{\frac{\pi}{a}} (2)

with n=2s a even number

for s=1 you have n=2, that is, the function g(x). By using the equation (2) (with a = 1) you finally obtain:

\int_0^{\infty}x^2e^{-x^2}dx=\frac{(2(1)-1)!}{2^{1+1}(1^1)}\sqrt{\pi}=\frac{\sqrt{\pi}}{4}

5 0
3 years ago
Read 2 more answers
Winnie Bracken opened a savings account at Dallas Trust Bank on March 1. It pays 4% interest compounded quarterly. She opened he
fiasKO [112]

The compounded interest is applied to the amount in the account at end

of a period specified in the rate of compounding.

  • The amount in the account at the end of 6 quarters is approximately <u>$16,767.2</u>

Reasons:

The interest paid on the account = 4% compounding

Amount with which she opened the account = $10,000

Amount she makes as deposit at the end of each quarter = $1,000

Therefore;

The interest per quarter = 4% ÷ 4 = 1%

Amount in the account after the end first quarter, A₁, is therefore;

A₁ = 10,000 × 0.01 + 10,000 + 1,000 = 11,100

The amount in the second quarter, A₂, is given as follows;

A₂ = 11,100 × 0.01 + 11,100 + 1,000 = 12211

A₃ = 12211 × 0.01 + 12211 + 1,000 = 13333.11

A₄ = 13333.11 × 0.01 + 13333.11 + 1,000 = 14466.4411

A₅ = 14466.4411 × 0.01 + 14466.4411 + 1,000 = 15611.105511

At the end of the 6th quarter, we have;

A₆ = 15611.105511 × 0.01 + 15611.105511 + 1,000 = 16767.2165991

The amount in the account at the end of 6 quarters, A₆ ≈ $16,767.2

Learn more about compounding interest rate here:

brainly.com/question/8806008

3 0
2 years ago
Read 2 more answers
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