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coldgirl [10]
3 years ago
11

Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal pl

ace. If there is more than one mode, enter your answer as a comma-separated list. If an answer does not exist, enter DNE.)
Points Scored by Lynn Points scored in a basketball game Frequency
2 10
3 9
9 10
11 7
12 3
15 4
16 3
Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer: Mean = 7.8

              Median = 9

             Mode = 2,9

Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

E(X)=\frac{2(10)+3(9)+9(10)+11(7)+12(3)+15(4)+16(3)}{10+9+10+7+3+4+3}

E(X) = 7.8

Mean for the given frequency distribtuion is 7.8.

<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:

1) Find total number, n:

n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46

2) Find position, using: \frac{n+1}{2}

\frac{n+1}{2}=\frac{47}{2} = 23.5

Median is in the 23.5th position.

3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9

Median for this frequency distribution is 9.

<u>Mode</u>  is the number or value associated with the highest frequency.

In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.

Mode for this distribution is 2 and 9.

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Answer:

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Step-by-step explanation:

The rule below is something I just found.

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5 0
3 years ago
Solve please solve what does x mean
Zinaida [17]

Answer:

x=65

Step-by-step explanation:

find the angles of the small square by completing the outer ones so the one on the left the missing one is 68 and the other side is 47, so 180= 68+47 + x

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5 0
2 years ago
21) Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the
diamong [38]

Answer:

Step-by-step explanation:

Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the

race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in

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First part :

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6 0
3 years ago
An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that
qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100

#First find F_x and probability distribution function ,f_x(x):

F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}

#Have determined the probability distribution unction ,f_x(x), we calculate the Expectation of the random variable X:

E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200}  dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\

#We then calculate E(X^2):

E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28

Hence, the Var(X) is 764.28  

4 0
3 years ago
Find two numbers whose product is 21 and whose sum is 10
Alex Ar [27]
The two numbers you are looking for are 7 and 3.
3 0
3 years ago
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