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aksik [14]
2 years ago
7

Ella completed the following work to test the equivalence of two expressions. 2 f + 2.6. 2 (0) + 2.6. 0 + 2.6. 2.6. 3 f + 2.6. 3

(0) + 2.6. 0 + 2.6. 2.6. Which is true about the expressions? The expressions are equivalent because Ella got different results when she substituted zero for f. The expressions are equivalent because Ella got the same result when she substituted zero for f. The expressions are not equivalent because Ella would get different results when substituting different numbers for f. The expressions are not equivalent because Ella would get the same results when substituting different numbers for f. IF YOU HELP I WILL GIVE BRAINLESS <33
Mathematics
2 answers:
Strike441 [17]2 years ago
7 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expressions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

klasskru [66]2 years ago
5 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

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andrew-mc [135]

Answer:  

ANSWER QUESTIONS 8, 9 AND 10 ACCORDING TO THE

NEXT INFORMATION

Luis painted a mural that

has 760 cm of

perimeter; your measurements are

show in the following

figure.

8. The expression associated with the length of the mural: 2x - 40, is

can interpret as

A. the length is 40 cm less than twice its width

B. the length exceeds the width value by 40 cm

C. the width squared, minus 40 cm, equals the length

D. 40 cm minus twice the width is the value of the length

9. What are the measurements in centimeters of the mural?

A. length: 150, width: 190 B. length: 210, width: 250

B. length: 210, width: 250

C. length: 240, width: 140 D. length: 230, width: 190

D. length: 230, width: 190

10. The area Luis used to paint the mural is

A. 2 [(2x - 40) + x] B. 2x2 - 40x

B. 2x2 - 40x

C. (2x) x - 40 D. x2 - 40x

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Step-by-step explanation:

6 0
3 years ago
What is the result when the number 86 is decreased by 9%?
Vikki [24]
78.26

Hope this helps!!!
6 0
3 years ago
What is:<br> <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B4x%5E%7B2%7D%20-20x%2B25%20" id="TexFormula1" title=" \sqrt{4x^{2} -
Firdavs [7]

We are given :

\sqrt{4x^{2}-20x+25}

Step 1: factor the part inside square root

The function given inside square root is of quadratic form.

So let us try to factorise it using AC method.

Here A*C = 4*25 = 100

so we have to find factors of 100 that add up to give -20.

the two factors are -10 and -10.

Rewriting the function :

4x^{2} -20x+25

=4x^{2} -10x-10x+25

=2x(2x-5) - 5(2x-5)

=(2x-5)^{2}

Step 2:

Now we take square root of the factorised form

\sqrt{(2x-5)^2}

= 2x-5

Answer : (2x-5)

3 0
3 years ago
How many Cube Bs will fit into Cube A? Enter the max amount.
KonstantinChe [14]

Answer:

8

Step-by-step explanation:

The answer is 8 because 1/2 times 1/2 times 1/2 is 1/8, which means that 8 B cubes can fit into cube A.

7 0
2 years ago
A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212
Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

  Weight of baby at birth  = 7.25 pounds

   

Unknown:

Weight at the end of 8months = ?

Solution:

 From the second sentence;

    Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

  Weight at the end of eighth month = 212 x  7.25  = 1537pounds

7 0
3 years ago
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