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aksik [14]
2 years ago
7

Ella completed the following work to test the equivalence of two expressions. 2 f + 2.6. 2 (0) + 2.6. 0 + 2.6. 2.6. 3 f + 2.6. 3

(0) + 2.6. 0 + 2.6. 2.6. Which is true about the expressions? The expressions are equivalent because Ella got different results when she substituted zero for f. The expressions are equivalent because Ella got the same result when she substituted zero for f. The expressions are not equivalent because Ella would get different results when substituting different numbers for f. The expressions are not equivalent because Ella would get the same results when substituting different numbers for f. IF YOU HELP I WILL GIVE BRAINLESS <33
Mathematics
2 answers:
Strike441 [17]2 years ago
7 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expressions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

klasskru [66]2 years ago
5 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

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