Answer:
The solution of the system of inequalities is the region above the right line y=(1/4)x+6 to the left of x=4; and above the right line y=2x-1 to the right of x=4
Step-by-step explanation:
The inequality y>(1/4)x+6 is the area above the right line y=(1/4)x+6
For x=0→y=(1/4)(0)+6→y=0+6→y=6; Point=(x,y)→Point=(0,6)
For x=4→y=(1/4)(4)+6→y=1+6→y=7; Point=(x,y)→Point=(4,7)
The inequality y>2x-1 is the area above the right line y=2x-1
For x=0→y=2(0)-1→y=0-1→y=-1; Point=(x,y)→Point=(0,-1)
For x=4→y=2(4)-1→y=8-1→y=7; Point=(x,y)→Point=(4,7)
Graphing the right lines (see the attached file), we can see the solution of the system: The region above the right line y=(1/4)x+6 to the left of x=4; and above the right line y=2x-1 to the right of x=4
