Bone growth in which the bone increases in diameter is called

1 answer:

8 0

Appositional growth is the term for the rise in diameter. The periosteum's osteoblasts build compact bone around the exterior bone surface.

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When conducting legal experiments on animals a researcher needs to obtain consent from the?

Alenkasestr [34]

When conducting legal experiments on animals, a researcher needs to obtain consent from the INSTITUTIONAL RESEARCH BOARD.
Each research institution has research board which sees into uses of animals for research purposes, consent must be obtained from the board before experiments involving usage of animals is carried out.

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3 years ago

vesna_86 [32]

Meiosis and mitosis are both preceded by one round of DNA replication; however, meiosis includes two nuclear divisions. The four daughter cells resulting from meiosis are haploid and genetically distinct. The daughter cells resulting from mitosis are diploid and identical to the parent cell.
so the similarities are:
-ways for cells to divide
-same number of chromosome as the original cell
-both have the basic 5 phases
-both processes go through chromosome replication
-Meiosis II is similar to Mitosis
I hope this is helpful :)))
have a nice day

4 0

4 years ago

A renewable resource

GrogVix [38]

Answer:

In my opinion ...it is option A:)

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2 years ago

Which of these statements describes one way that a nonrenewable energy resource is obtained?

Vladimir [108]

The correct answer is D

4 0

3 years ago

Read 2 more answers

Two insecticides will be compared for their effectiveness in eliminating aphids on tomato plants. Forty tomato plants of the Big

densk [106]

Answer:

The t-test

Explanation:

<em>The researcher should use a t-test to compare the two means and check if they are significantly different from each other.</em>

In using the t-test, both null (H0) and alternate (H1) hypothesis are made such that:

H0: n1 = n2
H1: n1≠ n2

Thereafter, the value of t is calculated and compared to its critical value on the table. The formula for calculating the t goes thus:

$t = \frac{Y_1 - Y_2}{\sqrt{\frac{S_1}{n_1} + \frac{S_2}{n_2} } }$

where, Y1 = mean of population 1, Y2 = mean of population 2, S1 = variance of population 1, S2 = variance of population 2, n1 = number of individuals in population 1 and s2 = number of individuals in population 2.

<em>At the end of the day, if the calculated t value is more than the critical value of t, the H0 is rejected and it shows that the two means are significantly different. Otherwise, the H0 is accepted and this shows that there is not significant difference between the mean of population 1 and that of 2.</em>

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3 years ago