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frosja888 [35]
3 years ago
7

Evaluate p+23 for p=8

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

31

Step-by-step explanation:

p = 8

p + 23

= 8 + 23

= 31

31 is the answer.

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Can someone solve these for me please
Grace [21]

Answer:

2. 16

3. 46

4. 59

Step-by-step explanation:

5.The measure of smaller angle is 87 degrees.

Step-by-step explanation:

Consider the provided information.

The provided angles are 3x degree and 2x + 25 degree.

Two angles are said to be Supplementary angles if their sum is 180 degree.

It is given that the provided angle are supplementary angles, thus

3x + 2x + 25 = 180

5x + 25 = 180

5x  = 180 - 25

5x  = 155

x = 31

Now, substitute the value of x in first angle i.e 3x.

3(31) = 93

Substitute the value of x in the second angle i.e 2x + 25

2(31) + 25 = 62 + 25 = 87

Hence, the measure of smaller angle is 87 degrees.

8 0
2 years ago
What is a name for a marked angle ? Answers to choose from :
katen-ka-za [31]

Answer:

Angles are named in two ways. You can name a specific angle by using the vertex point, and a point on each of the angle's rays. The name of the angle is simply the three letters representing those points, with the vertex point listed in the middle. You can also name angles by looking at their size.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Simplify the following expressions
qaws [65]

Answer:

1. -15c - 4

2. 3x - 5

3. 14q

4. -195 + 39m

5. 55b + 130

Step-by-step explanation:

6 0
2 years ago
What value of x makes the equation shown true? Show or explain what you did to get your answer. 5x – 1 = 19
Advocard [28]
5x-1=19
1st you add the one over to the 19 and you'll get 20
then you do 5x=20
divide the 5x over to the 20 and your final answer is 4.
5 0
3 years ago
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Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (
Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that I=\int_0^3 x^3-4x dx=9/4. We use the properties of integrals to write the new integrals in terms of I.

A) \int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2. We have used that ∫cf dx=c∫f dx.

B) \int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4. Here we used that reversing the limits of integration changes the sign of the integral.

C) It's the same integral in A)

4 0
3 years ago
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