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Inessa05 [86]
4 years ago
9

How do you solve this ?

Mathematics
1 answer:
TEA [102]4 years ago
4 0

JK=9x-11\\KL=5x+2\\JL=(9x-11)+(5x+2)=(9x+5x)+(-11+2)=14x-9\\\\JK+KL=JL\\\\\text{substitute}\\\\14x-9=10x+7\ \ \ \ |+9\\\\14x=10x+16\ \ \ \ |-10x\\\\4x=16\ \ \ \ |:4\\\\x=4\\\\JK=9x-11\to JK=9(4)-11=36-11=25

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Look at the geometry question and solve for X.
zubka84 [21]

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Step-by-step explanation:

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6 0
3 years ago
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kirill115 [55]
This question actually states 2930 divided by 5
We use this method by first seeing how was fives go into the first number
In this case no 5's go into 2 so we put a 0 above the line and carry over the 2 to the 9.
Out number now says 29, 5 fives gointo 29with a remainder of 4.
We write the 5 above the line and carry the four across.
We now have 43, 8 fives gointo 43 with a remainder of 3.
We write the 8 above the line and carry the 3.
Our last number now says 30, 6 fives gointo 30 exactly so we can just write 6 above the line.
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6 0
4 years ago
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kotegsom [21]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
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