<span>a. what is the frequency of the dominant allele in this population?
Let say N is dominant allele and n is the recessive allele. The disease is autosomal recessive so the patient should be homozygous recessive(nn).
If the frequency of nn is 1/750, then the frequency of n would be: </span>√(1/750)= 0.0365 = 3.65%<span>
b. assuming mating occurs at random in this population, what is the probability that a couple are both carriers of this disorder?
If the frequency of n is 3.65%, the frequency of N would be:
1=n+N
1=3.65%+N
N= 96.35%
The frequency of carrier(Nn) in population would be:
Nn= 2*N*n
Nn= 2 * </span>3.65% * 96.35%<span>
Nn= 0.0703
The chance that both of the parent is carrier would be: 0.07*0.07= 0.0049= 0.49%</span>
B. because organisms will adapt because of their environment so the adaption fit it.
Endocytosis was involved, according to the endosymbiotic theory.
Hope that helped!
<span>I believe that the answer is a. one day. After the egg leaves the ovaries it then travels to the fallopian tube where it sticks there waiting for it be fertilized. After a 24 hours of sticking in the fallopian and fertilization made. The ripe egg disintegrate and then either flies out of the body or absorb by the body.</span>
