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stepladder [879]
2 years ago
7

Find the unknown sides of the triangle

Mathematics
1 answer:
lesya [120]2 years ago
5 0

Answer:

The unknown side is 15 in.

Step-by-step explanation:

a^2+b^2=c^2

a^2+8^2=17^2

a^2+64=289

a^2=289-64

a^2=225

a=15

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3a + 10 − 4q + 7a − 4q − 6.
soldi70 [24.7K]

Answer:

Step-by-step explanation:

3a+10-4q+7a-4q-6  combine terms

10a-8q+4

7 0
3 years ago
Read 2 more answers
Help, two of these questions plz
Olenka [21]

Answer:

First Answer: y= 64 and x=64

Second Answer: 1&4, 2&3, 6&7, 5&8

Step-by-step explanation:

First Answer: 63 and ∠y is the same measure since there are

Second answer: They are vertical angles, each of the pairs of opposite angles made by two intersecting lines.

Hope this helps:)

4 0
3 years ago
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What percent of $90 = $45
Lynna [10]
45 is exactly half of 90
that means 45 is 50% of 90.
8 0
4 years ago
Which rational number is also an integer?<br> A) -82/6<br> B) -65/13<br> C) 43/5<br> D) 70/25
natulia [17]

Answer:

B

Step-by-step explanation:

Because all of the other ones are decimals and integers are WHOLE number positive or negative, and B is equal to -5

Hope This Helps

6 0
4 years ago
What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5
swat32

Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have y=-\dfrac{2}{3}x+5\to _1=-\dfrac{2}{3}

Therefore

m_2=-\dfrac{1}{-\frac{2}{3}}=\dfrac{3}{2}

We have the equation of a line: y=\dfrac{3}{2}x+b.

Put the coordinates of the point (8, 1) to the equation of a line:

1=\dfrac{3}{2}(8)+b

1=(3)(4)+b

1=12+b       <em>subtract 11 from both sides</em>

-11=b\to b=-11

Answer: \boxed{y=\dfrac{3}{2}x-11}

3 0
3 years ago
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