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stiv31 [10]
2 years ago
9

I’m about to cry from frustration. Help please before I die

Mathematics
2 answers:
kvv77 [185]2 years ago
7 0

Answer:

\frac{1}{3}x+16=37

63 Jelly Beans

Step-by-step explanation:

The unknown is the number of jelly beans originally in the bag or x

First he had x jelly beans

The he ate one-third of them

\frac{1}{3}x

He then ate 16 more jelly beans

\frac{1}{3}x+16

This was equal to 37 jelly beans

\frac{1}{3}x+16=37

This is the equation

Now solve for x

Subtract 16 from both sides

\frac{1}{3}x=21

Multiply both sides by 3

x=63

63 Jelly Beans

Strike441 [17]2 years ago
7 0
First you write the equation x+16=37. After solving you will get x=21. Then you multiply x by 3 to get the whole bag. And you will get 63
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Fifteen girls left a mixed group of boys and girls. There remained two boys for each girl. After this, 45 boys leave the group,
statuscvo [17]
Sorry i cant answer this way too hard for me
5 0
2 years ago
Susan paid $15.84 for a 7.48 - kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 - kg bag at a different store.
barxatty [35]

The unit price for the 7.48 is $2 kg per bag and the unit price for the 7.94 is $2 per kg bag, there is no difference in unit rates of both the bag.

<h3>What is unit rate?</h3>

A unit rate means a rate for one of something.

Given that, Susan paid $15.84 for a 7.48 kg bag of dog food. A few weeks later, she paid $16.58 for a 7.94 kg bag at a different store.

15.48/7.48 = $2/kg

16.58/7.94 = $2/kg

Hence, there is no difference in between both the bags, hence either of them are better.

For more references on unit rates, click;

brainly.com/question/11258929

#SPJ1

4 0
1 year ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
What is the value of z in the table?
Genrish500 [490]
The value is 30.9 liters
6 0
2 years ago
F(1) = 4, f(n) = f(n<br> − 1) + 11
zvonat [6]

Answer:

Step-by-step explanation:

You don't specify what you're supposed to do, so I'll make an educated guess.  

Given the sequence f(1) = 4, f(n) = f(n  − 1) + 11, find the first 5 terms:

f(1) = 4

f(2) = f(2 - 1) + 11 = f(1) + 11 = 4 + 11 = 15

f(3) = f(2) + 11 = 15 + 11 = 26

f(4) = f(3) + 11 = 26 + 11 = 37

f(5) = 37 + 11 = 48

4 0
3 years ago
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