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3 years ago

Solve pls brainliest

Mathematics

2 answers:

natima [27]3 years ago

7 0

Answer:

please brainliest would be much appreciated

eimsori [14]3 years ago

3 0

Answer:

Step-by-step explanation:

pls mark brainliest

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Please help me with the question below

nata0808 [166]

Answer:

Step-by-step explanation:

If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.

The second part tells us that Eden will be twice as old as Judge in two years.

This means that in two years: (Eden's age) = 2 * (Judge's age).

Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x

Simplify the equation:

x + 6 = 2x

6 = x = Judge's age (in two years)

If Judge is 6 two years later, then he must be 4 now.

To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.

6 0

3 years ago

lana [24]

Answer:20

Step-by-step explanation:

3 0

3 years ago

2(3/5n +3) - (2/3n-1)

borishaifa [10]

Hey there! :)

2(3/5n + 3) - (2/3n - 1)

Simplify.

(2 * 3/5n) + (2 * 3) - (2/3n -1)

Simplify.

6/5n + 6 - 2/3n + 1

Add like terms.

(6/5n - 2/3n) + (6 + 1)

Make the fractions have the same denominator by multiplying fraction 1 (6/5n) by 3/3 and fraction 2 (-2/3n) by 5/5.

6/5n * 3/3 = 18/15n

-2/3n * 5/5 = -10/15n

So, our new equation looks like this : (18/15n - 10/15n) + (6 + 1)

Simplify.

8/15n + 6 —> final answer.

Hope this helped! :)

4 0

3 years ago

Read 2 more answers

Tell whether (-8,2) is a solution of -x-6y>12

Dennis_Churaev [7]

Answer:

it ain't

Step-by-step explanation:

x = -8

y = 2

-(-8) - 2(6) > 12

8 - 12 > 12

-4 > 12

This is incorrect

6 0

3 years ago

Select all of the answers that are elements of M = {x | x is a month of the year}

BlackZzzverrR [31]

Answer:

{January, February, March, April, May, June, July, August, September, October, November}

Step-by-step explanation:

The set is formed by months of year with indexes larger than 0 and lesser than 12.

The year starts at month 1, which is January, and finishes at month 12, which is December.

Since we want lesser than 12, December is not part of the set. So the answer is given by:

{January, February, March, April, May, June, July, August, September, October, November}

6 0

3 years ago