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3 years ago

How many duckling were swimming at the pond?

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

There are 20 ducklings.

Step-by-step explanation:

For every group of 6 ducks, 5 would be ducklings.

24 / 6 = 4

There are 4 groups of ducks.

5 * 4 = 20

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A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa

Mkey [24]

Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = $\frac{12!}{3! 3! 3! 3!}$

Now,

The Total number of ways in which Remaining cards are distributed = $\frac{40!}{10! 10! 10! 10!}$

So,

Total number of ways of getting 3 picture card and remaining card = $\frac{12!}{3! 3! 3! 3!}$ × $\frac{40!}{10! 10! 10! 10!}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = $\frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }$

∴ The probability = $\frac{\frac{12! 40!}{(3!)^{4} (10!)^{4} }}{\frac{52!}{(13!)^{4} }}$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13!)^{4} }{ 52! }$

= $\frac{12! 40!}{(3!)^{4} (10!)^{4} }$ × $\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }$

= $\frac{12!}{(3!)^{4} }$ × $\frac{(13.12.11)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= $\frac{479,001,600}{(6)^{4} }$ × $\frac{(1716)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41}$

= 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

6 0

2 years ago

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gulaghasi [49]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Can someone solve this math problem for me

kolbaska11 [484]

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2 years ago

The main difference between a prokaryotic cell and a eukaryotic cell is

Aloiza [94]

the answer is the presence of a true nucleus

3 0

3 years ago

Read 2 more answers

One-third of 2c subtracted from five times nine

SOVA2 [1]

<span>One-third of 2c subtracted from five times nine
1/3 of 2c subtracted 5 x nine
1/3 x 2c - 5(9)
=1/3 x 2c - 45
=2c/3 - 45
if we solve for c,
2c/3 = 45
2c = 45 x 3
2c = 135
c = 135/2
c = 67.5</span>

4 0

3 years ago