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Anastaziya [24]
3 years ago
10

The waiters poured 160 eight-ounce glasses of water at the banquet. How many gallons is this? Show your work.

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0
160 * 8 = 1280 ounces.  1280/64 = 20  half gallons 20*1/2= 10      So you have 20 half gallons or 10 gallons.     
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25 students are learning how to make balloon animals. There are 194 balloons to be shared equally among the students. How many b
alexdok [17]
25 students
194 balloons

194/25 = 7.76
Each student gets 7 balloons, 7 x 25 = 175 balloons will be used
194 - 175 = 19 balloons remaining (Answer to part 1 of this question)

If each student needs 8 balloons
8 * 25 = 200
200 - 194 = 6 ballons needed (Answer to part 2 of this question)

We also could have found the answer to part 2 by saying that we had 19 balloons left over when the students each were given 7 balloons
Each student needs another 1 balloon = 25 balloons, 
We have 19 left over
25 - 19 = 6 balloons need to be purchased (we got the same answer both ways so it is very likely we have the correct answer)
6 0
3 years ago
Ming's DVD collection includes 16 adventures movies, 7 comedies, 12 westerns, and 8 mysteries. He wants to keep 8 of the DVDs an
alina1380 [7]

43 total movies the type of movies is added in to confuse you pay no ttention just add the total. he keeps 8 of them
43 - 8 = 35

he gives them to 5 friends

35 DIVIDED by 5 = 7

each friend would get 7 each

7 0
3 years ago
Can anyone help? It’s not 14, I’ll give Brainly + 15 pts
Julli [10]

Short side length = x

Medium side = x + 7

Long side = 5x

Total 49, so

x + x + 7 + 5x = 49

If you combine like terms:

7x + 7 = 49

Subtract 7 from both sides

7x = 42

Divide both sides by 7

x = 6 inches.

8 0
3 years ago
Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
Read 2 more answers
Which equation is the direct variation equation if f(x) varies directly with x and f(x)=-18 when x=3
Otrada [13]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  \stackrel{f(x)}{y}=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=-18\\
x=3
\end{cases}\implies -18=k3
\\\\\\
\cfrac{-18}{3}=k\implies -6=k\qquad therefore\qquad \boxed{\stackrel{f(x)}{y}=-6x}
5 0
3 years ago
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