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Anastaziya [24]
3 years ago
10

The waiters poured 160 eight-ounce glasses of water at the banquet. How many gallons is this? Show your work.

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0
160 * 8 = 1280 ounces.  1280/64 = 20  half gallons 20*1/2= 10      So you have 20 half gallons or 10 gallons.     
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A) 0
B) 6
C) middle number, or middle 2, averaged, so 3
D) 1
E) 4
F) 6-0 = 6
6 0
3 years ago
What is 276,431 rounded to the nearest ten thousand
viva [34]
The answer is 280,000 rounded to the nearest ten thousand.
3 0
3 years ago
Shishir bought 4000 orange at 70 paisa each. But 400 of them were rotten. He sold 2000 oranges at 90 paisa each.If he plans to m
Ipatiy [6.2K]

Answer:

He needs to sell the rest of the oranges at 75 paisa each.

Step-by-step explanation:

Consider the given information that, Shishir bought 4000 orange at 70 paisa each.

Note: 1 rupees = 100 paisa

Thus, 70 paisa = 70/100 rupees = 0.70 rupees

Therefore, the cost price of 4000 oranges is:

4000×0.70 rupees = 2800 rupees

The selling price of 2000 oranges is:

2000×0.90 rupees = 1800 rupees

The number of oranges now Shishir have:

4000 - 2000 - 400 = 1600

He wants to make a profit of RS 200. Thus the selling price of 4000 oranges should be:

2800 rupees + 200 rupees = 3000 rupees

He earned 1800 rupees by selling 2000 oranges at 90 paisa. So, the remaining amount that he needs to make with 1600 oranges is:

3000 rupees - 1800 rupees = 1200 rupees

Therefore, the cost of one orange is:

1600 oranges = 1200 rupees

1 orange = 1200/1600 rupees

1 orange = 0.75 rupees

Hence, he needs to sell the rest of the oranges at 75 paisa each.

4 0
3 years ago
Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation
evablogger [386]
Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)


sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4}  \\ \\   \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4}  )=1 \\  sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  =1 \\  cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4}  =1 \\
2cos(x)sin\frac{ \pi }{4}  =1    \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2}  \\ 2cos(x) \frac{ \sqrt{2} }{2}  =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x)   =1 \\   \sqrt{2} cos(x)=1 \\
cos(x)= \frac{1}{ \sqrt{2} }  \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z
6 0
2 years ago
A chocolate bar contains 6 grams of fat. If you eat no fewer than 5 and no more than 9 bars, how many grams of fat will you cons
IRINA_888 [86]

5 x 6 = 30

9 x 6 = 54

54 + 30 = 84

you would be intaking 84 grams of fat

8 0
1 year ago
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