Answer:
answer is c
Step-by-step explanation:
Common denominator
Common multiple
Simplest Form
GCF: Greatest Common Factor
LCM: Least Common Factor
Then Comparing Plain
<h2>
Hello!</h2>
The answers are:

<h2>
Why?</h2>
Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.
We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:


Have a nice day!
Exponential model because it's increasing rapidly.
Answer:
The solution is (3,13) and (-1,-3). So none of the mentioned options is correct.
Step-by-step explanation:
Given that


Now, by susbstituting the value of 'y' from equation i to equation ii, we get






Now by factorization, equation iii can be written as



x = 3 and x = -1
By putting the values of x in equation i, we get
y = 4(3) + 1
y = 12 +1
y = 13
and
y = 4(-1) + 1
y = -4 +1
y = -3
Therefore, the solution is (3,13) and (-1,-3). So none of the mentioned options is correct.