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2 years ago

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Mathematics

1 answer:

ki77a [65]2 years ago

3 0

Answer:

Step-by-step explanation:

I think it is a strangely worded question as they only refer to the larger gear turning.

I believe that this is what they are going for.

Number of teeth passing in each revolution

The Numbers match when the large gear turns two times as the smaller gear turns three times.

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Plizzz answer asap!!!!!

Anarel [89]

The letters spell "ADD AND SUBTRACT LIKE TERMS ONLY".

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2 years ago

PLEASE HELP!<br><br> What are the real and imaginary parts of the complex number?<br><br> -7+8i

klio [65]

Answer: The real part is -6

The imaginary part is 2i

Step-by-step explanation:

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3 years ago

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Which ordered pair (a,b) is a solution to the given system of linear equations.

egoroff_w [7]

Answer:

A. (-13,-3)

Step-by-step explanation:

Solve the system of two equations:

$\left\{\begin{array}{l}-2a+3b=14\\a-4b=3\end{array}\right.$

From the second equation:

$a=3+4b$

Substitute it into the first equation:

$-2(3+4b)+3b=14\\ \\-6-8b+3b=14\\ \\-8b+3b=14+6\\ \\-5b=20\\ \\5b=-20\\ \\b=-4$

So,

$a=3+4b=3+4\cdot (-4)=3-16=-13$

The solution is (-13,-4)

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3 years ago

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Which statement about inequalities is NOT true?

Anvisha [2.4K]

Answer:

D is incorrect and not true.

Step-by-step explanation:

if b is greater than a, a can't be greater than b.

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3 years ago

a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5

netineya [11]

9514 1404 393

Answer:

85 ones
70 fives
15 tens
2 fifties

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

a +5b +10c +50d = 685 . . . . . total amount of cash

b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

a = b+c . . . . . . . . . . . as many ones as fives and tens combined

d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

Substituting for 'a', then for 'b', we have ...

(b+c) +5b +10c +50d = 685

6(10 +4c) +11c +50d = 685

60 +35c +50d = 685

Substituting d=2 and subtracting 160 gives ...

35c = 525

c = 15

b = 10 +4c = 10 +4(15) = 70

a = b+c = 70 +15 = 85

The register contained ...

85 ones
70 fives
15 tens
2 fifties

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2 years ago

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