Which must be true of a quadratic function whose vertex is the same as the y-intercept ?

1 answer:

jeka943 years ago

3 0

A quadratic function whose vertex is the same as the y-intercept has the equation
y=x^2+k (where k is the y-intercept, with vertex (0,k))

Since the vertex coincides with the y-intercept, the axis of symmetry is x=0.

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What is the distance between tow points (1,5)(-8,4)

Degger [83]

Answer:

$\displaystyle d = \sqrt{82}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (1, 5)

Point (-8, 4)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-8-1)^2+(4-5)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-9)^2+(-1)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{81+1}$
[√Radical] Add: $\displaystyle d = \sqrt{82}$