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3 years ago

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Please helpppppppppppppppp

1 answer:

Zina [86]3 years ago

3 0

Answer:

29520728184915396206153835295

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The price of an item yesterday was $60. Today, the price fell to $42. Find the percentage decrease.

oksian1 [2.3K]

Answer:

-30% or 30% decrease

Step-by-step explanation:

What's percentage decrease?

Percent decrease is the difference between the initial value and new value, indicating a loss of value.
The formula to find percent decrease is $\frac{NV-IV}{IV} * 100$ , where NV = new value and IV = initial value.

How do we solve this problem?

We know that the original value was $60, so that represents IV. Also, now that the price is $42, it represents NV.
Now, we plug in the values!
$\frac{42-60}{60} * 100$
$\frac{-18}{60} * 100$
$-\frac{3}{10} * 100$
$-3 * 10$
$-30$

Therefore, the answer is 30% decrease.

6 0

2 years ago

Solve the following equations;-<br><br> x - 9 /√x + 3 =1

fgiga [73]

Answer:

13 , 6.

Step-by-step explanation:

A equation is given to us and we need to find out the value of x . The given equation to us is ,

$\sf\implies \dfrac{ x -9}{\sqrt{x+3}}= 1$

Cross multiply ,

$\sf\implies x - 9 =\sqrt{ x +3}$

Squaring both sides ,

$\sf\implies (x - 9)^2 = x + 3$

Simplify the whole square ,

$\sf\implies x^2+9^2-2.9.x = x +3 \\$

$\sf\implies x^2+81 - 18x = x -3$

Add 3 and subtract x on both sides ,

$\sf\implies x^2 -18x-x +81-3=0$

Simplify ,

$\sf\implies x^2 -19x +78=0$

Split the middle term of the quadratic equation,

$\sf\implies x^2-13x-6x+78=0$

Take out common ,

$\sf\implies x( x -13)-6(x-13)=0$

Take out ( x -13 ) as common ,

$\sf\implies ( x -13)(x-6)=0$

Equate both factors to 0 ,

$\sf\implies \boxed{\pink{\sf x = 13,6}}$

<u>Hence</u><u> the</u><u> </u><u>value</u><u> of</u><u> </u><u>x</u><u> is</u><u> </u><u>1</u><u>3</u><u> </u><u>or </u><u>6</u><u> </u><u>.</u>

7 0

3 years ago

If Susan earn 1,800 per month and her rent is 504 per month, what percent of her income is spent on rent?

svetoff [14.1K]

504÷1800=0.28
28% of her income goes to her rent

4 0

3 years ago

Let a, n, b, r, and k be integers. If a = nb+r and k|a and k|b, then k|r

Kryger [21]

Answer:

Proof for $k|r$

Step-by-step explanation:

We are given that a, n, b, r and k are integers.

Also,

$a = nb + r$

Since k divides a and b, we can write,

a = rk and b = sk, where r and s are integers.

Now, we have to prove that k divides r as well that is $k|r$

Putting value of a and b in the equation, we get:

$rk = n(sk) + r\\r = rk - nsk\\r = (r-sn)k$

Since, (r-sn) is an integer, k divides r.

5 0

3 years ago

Which of the following numbers is irrational?

Nastasia [14]

The believe the answer would be D.

7 0

3 years ago