The number of mole of the gas present in the sample which occupies a volume of 350 mL at 25 °C and 1 atm is 0.0143 mole
From the question given above, the following data were obtained:
Volume (V) = 350 mL = 350 / 1000 = 0.35 L
Temperature (T) = 25 °C = 25 + 273 = 298 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
<h3>Number of mole (n) =? </h3>
With the application of the ideal gas equation, the number of mole of the gas present in the sample can be obtained as follow:
<h3>PV = nRT </h3>
1 × 0.35 = n × 0.0821 × 298
0.35 = n × 24.4658
Divide both side by 24.4658
n = 0.35 / 24.4658
<h3>n = 0.0143 mole </h3>
Therefore, the number of mole of the gas present in the sample is 0.0143 mole
Learn more: brainly.com/question/9731218
It’s occasionally used to remove static electricity in machinery or dust from photographic film. it can be used as a lightweight heat source for thermoelectric power in space satellites.
Answer:
Higher fluid resistance
Explanation:
Because the fluid become compressible the fluid resistance increase
The chemical formula tells us the mole ratio. CO2 = 1 CO2 molecule : 1 C atom : 2 O atoms. 1 C12H22O11 molecule: 12 O2 molecules : 12 CO2 molecules : 11 H2O molecules.
Answer:
0.074
Explanation:
15% means that in 100 g of solution 15 g sodium hydroxide is present.
Mass of water = 100 - 15 = 85 g
Number of moles of sodium hydroxide:
Number of moles = 15 g/40 g/mol
Number of moles = 0.375 mol
Number of moles of water:
Number of moles = 85 g/18 g/mol
Number of moles = 4.7 mol
Moles fraction of NaOH:
moles of NaOH/ moles of solvent + moles of solute
0.375 mol/ 0.375 mol+4.7mol
0.375 mol / 5.075 mol
0.074