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Margarita [4]
4 years ago
13

What is the mole fraction of NaOH in an aqueous solution that contains 15% NaOH by mass?

Chemistry
1 answer:
zhenek [66]4 years ago
6 0

Answer:

0.074

Explanation:

15% means that in 100 g of solution 15 g sodium hydroxide is present.

Mass of water = 100 - 15 = 85 g

Number of moles of sodium hydroxide:

Number of moles = 15 g/40 g/mol

Number of moles = 0.375 mol

Number of moles of water:

Number of moles = 85 g/18 g/mol

Number of moles = 4.7 mol

Moles fraction of NaOH:

moles of NaOH/ moles of solvent + moles of solute

0.375 mol/ 0.375 mol+4.7mol

0.375 mol / 5.075 mol

0.074

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A buffer is prepared by dissolving honh2 and honh3no3 in some water. write equations to show how this buffer neutralizes added h
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3. How many atoms are found in 5.20 g of magnesium (Mg)?
Ganezh [65]

Explanation:

In order to go from mass of magnesium to atoms of magnesium, we have to do two things:

   Convert mass of Mg to moles of Mg using the molar mass of Mg as a conversion factor

   Convert moles of Mg to atoms of Mg using Avogadro's number (6.02×1023) as a conversion factor

Step 1:

Before we start, I should note that the molar mass of Mg is 24.31gmol. We can go from mass to moles using dimensional analysis. The key to dimensional analysis is understanding that the units that you don't need any more cancel out, leaving the units that are desired:

48.60g

×1mol24.31g

=2.00mol

Step 2:

We'll use this relationship:

www.sprinklernewz.uswww.sprinklernewz.us

Using the moles of Mg that we just obtained, we can use Avogrado's number to perform dimensional analysis in order to cancel out units of mol to end up with atoms of Mg:

2.00mol

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=1.204×1024atoms

Thus, 48.60g of Mg is equivalent to 1.204×1024atoms

Hope this helped :)

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