Answer:
Solid to liquid
Explanation:
Entropy is a state of randomness or disorderliness of the particles of a system. Some part of the heat energy of a system is related to the state of disorder or randomness of the particles of the system.
The entropic level of a system depends on two of major factors:
1. Temperature: Entropy increases with temperature rise due to the fact that the randomness of the particles of a system increases at a higher temperature.
2. Physical state of matter: The increasing order of entropy is:
Solid < Liquid < Gas
Gases are the most disordered and have the highest entropy. In moving from solid to liquid to gas, entropy of a system would increase.
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For one and two, I could not find anything. I highly suggest you talk to your textiles teacher for both one, two, and five, and review the whole assignment with them.
3.)- Lifting and shifting the iron to produce more steam and less wrinkles on a garment
4.) Using the "wrong" side of the garment to make it more rigid
5.) Seam along the interface
6.) Before one puts a new garment for the first time in the laundry.
Thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
<h3>What are the products of
Uranium-238 and Thorium -228?</h3>
If an atom of Uranium-238 decays via alpha emission, a nucleus of uranium 238 decays by alpha emission to form a daughter nucleus, thorium 234 while If an atom of Thorium -228 decayed via beta emission, the daughter isotope is protactinium 234.
So we can conclude that thorium 234 is the daughter product of Uranium-238 decays whereas protactinium 234 is the daughter product of Thorium -228.
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the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g
The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn
3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2
the formula is n= mass/M so, now substituting values
m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3
so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g
so mass of aluminum oxide obtained = 1.36g
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