The number of mole of the gas present in the sample which occupies a volume of 350 mL at 25 °C and 1 atm is 0.0143 mole
From the question given above, the following data were obtained:
Volume (V) = 350 mL = 350 / 1000 = 0.35 L
Temperature (T) = 25 °C = 25 + 273 = 298 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
<h3>Number of mole (n) =? </h3>
With the application of the ideal gas equation, the number of mole of the gas present in the sample can be obtained as follow:
<h3>PV = nRT </h3>
1 × 0.35 = n × 0.0821 × 298
0.35 = n × 24.4658
Divide both side by 24.4658
n = 0.35 / 24.4658
<h3>n = 0.0143 mole </h3>
Therefore, the number of mole of the gas present in the sample is 0.0143 mole
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