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3 years ago

(1, 3) and (-3, -5) write a linear equation given the two points

Mathematics

1 answer:

Firlakuza [10]3 years ago

7 0

Answer:

y = 2x + 1

Step-by-step explanation:

1. Find the slope; (change in y values)/(change in x values)

Slope = (-5 - 3)/ (-3 - 1) = -8/-4 = 2

2. Find the y-intercept (b) using the slope intercept formula: y = mx + b

m = 2 and using point (1, 3) , solve for "b"

y = mx + b

3 = 2(1) + b

3 = 2 + b

1 = b

3. Write the linear equation: y = 2x + 1

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X - 5(x - 1) = x - (2x - 3)

m_a_m_a [10]

X=2/3 I hope this helps

3 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

0.8 >0.78<br> True or false?

ElenaW [278]

Answer:

true

Step-by-step explanation:

.8 is closer to 1 than .78 is

8 0

3 years ago

Find the number of terms and the degree of this polynomial -3p^8+2p^2-5

Hoochie [10]

Answer:

The degree if the polynomial is 8.

Step-by-step explanation:

When the polynomial is of the form ax^n+bx^(n-1)+.........+c, then n is the degree of the polynomial which in this case is 8.

as the given polynomial has three terms so it is trinomial.

3 0

3 years ago

What is the value of x in the equation one-fifthx – two-thirdsy = 30, when y = 15? 4 8 80 200.

worty [1.4K]

On solving the linear system, for the value of y = 15, the value of x is 200. The correct option is D.

<h3>What is the linear system?</h3>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

Given

The linear equation is shown below.

$\rm \dfrac{1}{5}x - \dfrac{2}{3}y = 30$

The equation can be written as

$\rm 3x - 10y = 450\\$

For y = 15, the value of x will be.

$\begin{aligned} \rm 3x - 10*15 &= 450\\\\\rm 3x - 150 &= 450 \\\\\rm 3x &= 600\\\\\rm x &= 200\\\end{aligned}$

The value of x is 200.

Thus, option D is correct.

More about the linear system link is given below.

brainly.com/question/20379472

7 0

3 years ago