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Firdavs [7]
3 years ago
9

. Gold has a density of 19.32 g/cm3. If a square pyramid has a base edge length of 5 cm, height of 6 cm, and a mass of 942 g, is

the pyramid in fact solid gold? If it is not, what reasons could explain why it is not? Recall that density can be calculated with the formula density=mass /volume
Mathematics
2 answers:
aalyn [17]3 years ago
7 0

Answer:

See below in bold.

Step-by-step explanation:

The volume of the pyramid = 1/3 * area of base * height  = 1/3 * 6 * 5^2

= 50 cm^3.

Now we work out the density assuming it is solid gold

Density = mass / volume = 942 / 50 = 18.84, but the density of gold is 19.32 g/cm^3  so the pyramid cannot be solid gold.

trapecia [35]3 years ago
3 0

Answer:

The answer to your question is: It is not made of gold.

Step-by-step explanation:

Data

density = 19.32 g/cm³

side = 5 cm

height = 6 cm

mass = 942 g

Formula

                          V = \frac{1}{3} L^{2}  h

L² = 5 x 5 = 25 cm²

                          V = \frac{1}{3} 25 x 6

                          V = 50 cm³

density = 942 g / 50 cm³

            = 18.84 g/cm³  

It is not made of gold because the density calculated is lower than the density reported in books.

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shutvik [7]

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3 0
2 years ago
Test #
Agata [3.3K]
5 is the slope and 3 is the y-intercept
7 0
3 years ago
Water freezes at 0 degrees Celsius. A student discovered that adding half a cup of salt to a gallon of water lowers its freezing
Artemon [7]

Answer:

-7°C

Step-by-step explanation:

Freezing point of water = 0°C

By adding salt, freezing point lowers by 7°C ;

The freezing point of salt water can be expressed as ;

Since temperature lowers :

Freezing point of salt water :

Freezing point of water - 7°C

0°C - 7°C

= - 7°C

4 0
3 years ago
Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.
Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0
3 years ago
S - 10,000 = 3,753<br><br>A. s = 13,573<br><br>B. s = 13,753<br><br>C. s = 10,375
Lesechka [4]

Answer:

B. s = 13753

Step-by-step explanation:

s - 10000 = 3753

To find value of s, add both sides by 10000

s - 10000 = 3753

   +10000    +10000

-----------------------------------

s = 13753

6 0
3 years ago
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