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julia-pushkina [17]

2 years ago

7

If A : B = 5 : 8 and B : C = 4: 3, A : B : C =??

1 answer:

Otrada [13]2 years ago

5 0

Answer:

A:B:C = 5:8:6

Step-by-step explanation:

You don't have to change A, you only have to change B and C in the second ratio given. First, B is 8 and secondly, B is 4. You can multiply 4 in the second ratio and make it 8, but, remember, <em>always do the same change to the other side too</em>. So, if you change the 4 to 8 by multiplying by 2, multiply 3, which is C, by 2 too. Then, you get B:C as 8:6. Lastly, you get the final answer as 5:8:6.

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1)

n 1 2 3 4 5 6

f(n) 1033 932 831 730 629 528

First term (a₁): <u>1033 </u> Common difference (d): <u>-101 </u>

Explicit rule: $a_{n} = 1134 - 101n$ Recursive rule: $a_{n} = a_{n-1} - 101$

$a_{n} = a_{1} + d(n - 1)$

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$a_{n} = 1134 - 101n$

***********************************************************************************

2)

n 1 2 3 4 5 6

f(n) -39 -29 -19 -9 9 19

First term (a₁): <u> -39 </u> Common difference (d): <u> +10 </u>

Explicit rule: $a_{n} = -49 + 10n$ Recursive rule: $a_{n} = a_{n-1} + 10$

$a_{n} = a_{1} + d(n - 1)$

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***********************************************************************************

3)

n 1 2 3 4 5 6

f(n) 3.75 2.5 1.25 0 -1.25 -2.5

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Explicit rule: $a_{n} = 5 - 1.25n$ Recursive rule: $a_{n} = a_{n-1} - 1.25$

$a_{n} = a_{1} + d(n - 1)$

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