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3 years ago

A translation moves point X to X' using the rule (x,y) → (x-2, y + 1). If X' is (3,-4), what was the

Mathematics

1 answer:

Dimas [21]3 years ago

3 0

Answer:

X' is (5,-5)

Step-by-step explanation:

Knowing that this is just a translation, we can reverse the (polarity?) of each equation, such as changing -5 to +5 to find the original answer.

With that in mind, we can add 2 to X, and -1 from Y, which puts us at, 5 on the X axis, and -5 on the Y axis.

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PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

aivan3 [116]

Hello and Good Morning/Afternoon

Let's take this problem step-by-step:

To find the solution to a system of equation

⇒ must set the equations equal to each other

⇒ and solve

Let's put that into action

$x^2-2x+3 = -2x + 12\\x^2-2x+2x+3-12=0\\x^2-9=0\\(x+3)(x-3)=0$

At this point, to make the whole thing equal zero

⇒ either 'x+3' or 'x-3' equals zero

⇒ must find 'x' that satisify either equation

$x-3=0\\x=3\\\\x+3=0\\x=-3$

Let's find the corresponding f(x) to each x-value

$f(3) = -2(3)+12=-6+12 = 6\\\\f(-3) = -2(-3) + 12=6+12=18$

Therefore the solutions are (3,6) and (-3,18)

Answer: (3,6), (-3,18)

Hope that helps!

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