<span>0.570 M (note the capital M, this is molarity. Using m denotes molality.
Molarity is represented by moles of solute over the liters of solution. In this problem we are given the mass of the solute and volume of solution. The calculations is follows:
(15.7 g CaCO3/275 mL of solution) x (1 mole CaCO3/ 100.0869 g of CaCO3) x (1000 mL of solution/ 1 L of solution) = 0.570 M CaCo3.</span>
Answer:
Solution. So, the empirical formula of the compound is NH2.
Explanation:
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Answer:
The answer is B) The law of conservation of energy.
Explanation:
This is the answer because energy cannot be created or be destroyed in a isolated system. The second law as well states that the entropy of any isolated system always increases.
Given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.
<h3>How to calculate mass of substances?</h3>
The mass of a substance can be calculated using the following steps:
Cu + 2AgNO3 = Cu(NO3)2 + 2Ag
1 mole of Cu react with 2 moles of AgNO3
- Molar mass of AgNO3 = 169.87 g/mol
- Molar mass of Cu = 63.5g/mol
moles of AgNO3 = 262g/169.87g/mol = 1.54mol
1.54 moles of AgNO3 will react with 0.77 moles of Cu.
mass of Cu = 0.77 × 63.5 = 48.97g
Therefore, given the following equation; Cu + 2AgNO3 = Cu(NO3)2 + 2Ag, 48.97 grams of Cu are needed to react with 262g of AgNO3.
Learn more about mass at: brainly.com/question/6876669