Answer:
Heat transfer during melting of ice plays greater role in cooling of liquid water.
Explanation:
Temperature of ice = -10 °c
Temperature of water = 0 °c
When ice cube is dipped in to the water.the heat transfer
Q = m c ΔT
⇒ Q = 1 × 2.01 × 10
⇒ Q = 20.1 KJ
Heat transfer during melting of ice
= latent heat of ice
Latent heat of ice = 334 KJ
⇒
= 334 KJ
Heat transfer during melting of ice is greater value than heat transfer during warming of ice from -10°C to 0°C.
Thus heat transfer during melting of ice plays greater role in cooling of liquid water.
In that case, the salt<span> would be the </span>solvent<span> and the </span>water<span> the </span><span>solute.
So, it would be solution!
Have a nice day! :D</span>
Answer:
The volume is 59, 3 liters. See the explanation below, please
Explanation:
STP conditions (standard) correspond to 273K of temperature and 1 atm of pressure. These values are used and the volume is calculated, according to the formula:
PV = nRT
1 atm x V= 2, 65 moles x 0, 082 l atm/K mol x 272 K
V= 2, 65 moles x 0, 082 l atm/K mol x 272 K/1 atm = 59, 3 liters