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KengaRu [80]
2 years ago
8

The diagonals of a rectangle ABCD meet at O if AO=(2x+3)cm and DO=(5x)cm find the length of its diagonals also find the perimete

r of the rectangle if AB=8cm.
​
Mathematics
1 answer:
vfiekz [6]2 years ago
3 0

Step-by-step explanation:

AO = DO

2x+3 = 5x

3 = 5x-2x

3 = 3x

x = 1

DO = 5(1)=5cm

AC = 2×5 = 10cm

BC =√10²-8²

= √100-64

=√36

=6 cm

therefore, the perimeter of the rectangle

= 2×(8+6) = 2(14) = 28 cm

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\bf \textit{perimeter of a rectangle}=p=side+side+side+side
\\\\
or\implies p=w+w+l+l\implies p=2w+2l
\\\\
p=2(w+l)\qquad 
\begin{cases}
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------\\
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-----------------------------\\\\
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\bf thus\qquad 
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