Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Answer: -279
Step-by-step explanation:
-129-150= -279
to check
-279+150= -129
Given:
Cone shape: radius = 24 cm ; height = 6cm
Cylinder: radius = 16cm
We need to find the volume of each shape.
Volume of a cone = π r² h/3 = 3.14 * 24² * 6/3 = 3.14 * 576 * 2 = 3,617.28
Volume of a cylinder = π r² h
3,617.28 = 3.14 * 16² * h
3,617.28 = 3.14 * 256 * h
3,617.28 = 803.84 h
3,617.28 / 803.84 = 803.84h/803.84
4.5 = h
The height of the cylinder is 4.5cm
Answer: 56 times
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Let the three numbers be x, y, and z.
If the sum of the three numbers is 3, then x+y+z=3
If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9
If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5
This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5
First, to find y, let's take do [1]-[2]:
x+y+z=3
-x+y-z=-9
2y=-6
y=-3
Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4
Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2
So the three numbers are 2,-3, and 4.
