I would appreciate some help with this!

How many 4-digit odd numbers can you make using the digits 1 to 7 if the numbers must be less than 6000? No digits are repeated.

bixtya [17]

Answer:

Step-by-step explanation:he first digit must be a 6, 7, or 8, because the number has to be bigger than 6,000.

The last digit must be a 1, 3, 5, or 7, because the number has to be odd.

So if the first digit is 6 or 8, there are 4 odd-number options for the last digit. If the first digit is a 7, then there are only 3 options for the last digit, as 7 can’t be used twice.

The other two digits can be anything that’s not already used. So for each first-and-last combination of digits mentioned above, there will be six options available for one of the middle digits, and then for each of those 3-digit combinations, five options will be available for the final remaining digit.

At this point, we have everything we need to express this as an equation:

x = (2 x 4 + 1 x 3) x 6 x 5

And then we can simplify and solve:

x = (8 + 3) x 30

x = 11 x 30

x = 330

6 0

3 years ago

What is 5x/3 = 80/12 solve for x

Over [174]

X=4

explanation:
-reduce the fraction
-make the numerators equal
-divide both sides by 5

8 0

3 years ago

Solve the equation: (x − 4)(x − 3) = 0

trasher [3.6K]

Answer:

x=4, x=3

Step-by-step explanation:

This is most often the format taken from the polynomial form of this problem, which is x^2-7x+12, and when it is in this format you just take each set of numbers within each parenthesis and set it to zero, then solve. In this case, x can be equal to either 3 or 4.

8 0

3 years ago

If the weight (in grams) of cereal in a box of Lucky Charms is N(489,6), what is the probability that the box will contain less

Wittaler [7]

Answer:

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N(489,6)

This means that $\mu = 489, \sigma = 6$