Comparing graphs of functions Which function has the greatest y-intercept?

Can anyone explain what Literal Equations are? PLZ.

melisa1 [442]

Answer:

A literal equation is an equation that consists of multiple variables or letters.

A linear equation is an equation that consists of one variable

Step-by-step explanation:

Literal EX:

a = 1/2h(a + b)

ax + b = c

u = ak/b

Linear EX:

5(3a + 8) = 12a

4a = 8

11(3a - 18) = 12a

4 0

3 years ago

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Can some one please help cause I don't understand it

lilavasa [31]

The answer is the (It’s the last two.)

Enjoy :)

8 0

3 years ago

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Sis In order to identify the zeros of the function, a student factored the cubic function ()=−−f of , open x close , equals , x

creativ13 [48]

Answer:

f(x)=x(x-5)(x+2)

Step-by-step explanation:

Since the steps of the factorization of the polynomial f(x) is not given, I will proceed to give the correct factorization of f(x).

f(x)=x³-3x²-10x

First, we factor out x since it is a common term.

f(x)=x(x²-3x-10)

Next, we factorize the quadratic expression x²-3x-10.

f(x)=x(x²-5x+2x-10)

f(x)=x(x(x-5)+2(x-5))

f(x)=x(x-5)(x+2)

The correct factorization of the polynomial f(x)=x³-3x²-10x is: f(x)=x(x-5)(x+2)

7 0

3 years ago

A line passes through the point (4, -6) and has a slope of 3/2 . Write an equation in slope-intercept form for this line.

tatyana61 [14]

A slope intercept form: y = mx + b where m = slope and b = y -intercept

A slope of 3/2 is given

So y = 3/2 x + b

To find b:

b = y - mx

A line passes through the point (4, -6)

b = -6 - (3/2)(4)

b = -6 - 6

b = - 12

Answer

Equation in slope intercept form: y = 3/2 x - 12

8 0

3 years ago

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A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus

aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis $H_0:\mu= 1.6$ (the null hypothesis always have the equal sign).

We have to test the null hypothesis

$H_0:\mu= 1.6$

The significance level for this test is 0.05

Calculation of the t-statistic:

$t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47$

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject $H_0: \mu= 1.6$ , we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0

3 years ago