Question

Indicate in standard form the equation of the line through the given points. K(6, 4), L(-6, 4)

Answer 1

Answer:

$y=4$

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

The equation of the line in Standard form is:

 $Ax + By =C$

Where A, B, and C are integers.

We can find the slope of this line with this formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Given the points K(6, 4) and L(-6, 4), we get:

$m=\frac{4-4}{-6-6}=0$

Substituting the value of "m" and the coordinates of any point on the line into the equation and solving for "b", you get:

$4=0(6)+b\\b=4$

Therefore, the equation of this line is:

$y=4$

Answer 2

y=4

the values of x changes while the y doesn't so it's y=4