1 answer:
Answer:
we know that
case a) alternate exterior angles
m∠2=m∠7 --------> by alternate exterior angles
m∠1=m∠8 --------> by alternate exterior angles
case b) alternate interior angles
m∠3=m∠6 --------> by alternate interior angles
m∠5=m∠4 --------> by alternate interior angles
case c) corresponding angles
m∠1=m∠5 --------> by corresponding angles
m∠3=m∠7 --------> by corresponding angles
m∠2=m∠6 --------> by corresponding angles
m∠4=m∠8 --------> by corresponding angles
case d) vertical angles
m∠1=m∠4 --------> by vertical angles
m∠2=m∠3 --------> by vertical angles
m∠5=m∠8 --------> by vertical angles
m∠6=m∠7 --------> by vertical angles
therefore
the answer in the attached figurewe know that
case a) alternate exterior angles
m∠2=m∠7 --------> by alternate exterior angles
m∠1=m∠8 --------> by alternate exterior angles
case b) alternate interior angles
m∠3=m∠6 --------> by alternate interior angles
m∠5=m∠4 --------> by alternate interior angles
case c) corresponding angles
m∠1=m∠5 --------> by corresponding angles
m∠3=m∠7 --------> by corresponding angles
m∠2=m∠6 --------> by corresponding angles
m∠4=m∠8 --------> by corresponding angles
case d) vertical angles
m∠1=m∠4 --------> by vertical angles
m∠2=m∠3 --------> by vertical angles
m∠5=m∠8 --------> by vertical angles
m∠6=m∠7 --------> by vertical angles
therefore
the answer in the attached figure
Step-by-step explanation:
THIS IS NOT MY ANSWER
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Answer:
Step-by-step explanation:
First you can find the slope of the line that would pass through those two points using the formula:
m =
m =
m=5/4
Now you can just plug the slope and one of the points into point-slope form for an equation of the line that will pass through both points. You can choose either point here: I'll just use the first one.
So,
(don't leave out the parentheses!)
I think this is how you solve this
Step-by-step explanation:
look at the attachment......
The phrases that fit the graph of are
- curve positive x-values
- point (1, 1) x-intercept = 0
- quadrant I y-intercept = 0
The equation of the function is given as:
Next, we plot the graph of the function (see attachment)
From the attached graph, we have the following highlights:
- All points are in quadrant I
- The function is a curve
- It has an x-intercept of x = 0
- It has a y-intercept of y = 0
- It has only positive x values
- It passes through (1,1)
The above represents the phrases that fit the graph
Read more about features of a function at:
#SPJ1
<h3>Complete question</h3>Using a graphing application, graph y = √x. Sketch the graph below.
Select all phrases that fit the graph of y = √x
curve straight y-intercept = 1 positive x-values
quadrant IV quadrant III point (1, 1) x-intercept = 0
quadrant I y-intercept = 0 no y-intercept negative y-values
no x-intercept quadrant II x-intercept = 1 point (-1, -1)
