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MAVERICK [17]
2 years ago
13

Divide.

Mathematics
2 answers:
In-s [12.5K]2 years ago
8 0

Hii

The answer us - 5/4

Sorry if incorrect

DerKrebs [107]2 years ago
7 0

( \frac{5}{6} ) \div ( \frac{2}{3}) \: multiply \: by \:  \: the \:  \: reciprocal \\  \\  \frac{5}{6}  \times  \frac{3}{2}  \:  \:  \: reduce \: the \: numbers \\  \\  \frac{5}{2}  \times  \frac{1}{2} then \: multiply \\ \\  \\  =  \frac{5}{4}  \\  \\ hope \:  \: it \:  \: helps

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I need help with this
SVETLANKA909090 [29]

Answer:

The answer is 0.675

Step-by-step explanation:

If you were going to ask Brainly, you could have easily just used a calculator lol

4 0
3 years ago
The difference of twice a number and 3 is 11
Softa [21]
Let's break this down:

The difference: Something's gotta be subtracted
Twice a number: So 2 times a number, or n
and 3: So we gotta subtract 2n and 3
is 11: The final answer is 11
So altogether is:

2n - 3 = 11
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3 years ago
If x=0. Find the value of 8x-2(6-x)
Harrizon [31]

Answer:

-12

Step-by-step explanation:

8x - 2(6 - x)

Substitute 0 for each x

8*0 - 2(6 - 0)

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0 - 2*6

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7 0
3 years ago
Read 2 more answers
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p
PIT_PIT [208]

Answer:

Colin has <em>8 sheets </em>left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = x

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8

So, the answer is:

Colin has <em>8</em> <em>sheets </em>left for his third class.

5 0
3 years ago
Please help me
GrogVix [38]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
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