Answer:B and E
Step-by-step explanation:
Answer: a) 46 minutes
b) 10:47
The basic knowledge for this is that 60 minutes = 1 hour
<u>a)</u> Question a asks for how long it took from a 10:34 bus from Mosley to reach Bamford. From the table you can see that the 10:34 bus reaches Bamford at 11:20. All you have to do is count from 10:34 to 11:20.
10:34 will become 11:00 at 10:60 right? Clock's generally don't show 10:60 but goes directly to 11:00 after 1 minute is passed at 10:59. So from 10:34 to 11:00, it takes 26 minutes. Remember the bus reaches at 11:20 so from 11:00 to 11:20, it takes 20 minutes. Now add them up:
26 minutes + 20 minutes = 46 minutes
Here you go! Total 46 minutes from Mosley to Bamford.
<u>b)</u> From question b, we can see that Trina did not ride the first bus or by any chance missed it because the bus left at 10:14 and she is at the station at 10:15. Now think it from your perspective! You missed the first bus and you are in a big rush. So to reach your destination as early as possible, you will obviously take the next earliest bus. The next bus is at 10:24 (Belton). So if we take the 10:24 bus in Belton, it reaches at 10:47 in Garton.
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Answer:
p(x) = 0.85x
t(x) = 1.065x
(t o p)(x) = 0.9x
$2700
Step-by-step explanation:
If the marked price is $x, then the function p(x) that gives the price of the riding lawn mower after 15% discount will be
where x is the marked price.
Now, the function that gives the total cost with sales tax will be given by
where x is the discounted price.
Therefore, the composite function that gives the total cost of the riding lawn mower on sale is given by
(t o p)(x) = 1.065(0.85x) = 0.9x ............ (1)
where x is the marked price.
If the marked price x = $3000, then Mr. Rivera has to pay for the riding lawn mower, from equation (1),
(t o p)(3000) = 0.9 × 3000 = 2700 dollars. (Answer)
Answer:
I don't really know
Step-by-step explanation:
I don't really know but if you want to find out math questions try this website called wolfram alpha. It's great with those type of stuff.
