Answer:
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Step-by-step explanation:
Given data
mean = 5.1 millimeters (mm)
standard deviation = 0.7 mm
to find out
percent (%) of ancient prehistoric thinner than 3
solution
we have given mean and SD
so Z will be = x -mean / SD
Z = ( x - 5.1 ) / 0.7
so P( x < 3 ) = P ( (x - 5.1 ) / 0.7 < ( 3 - 5.1 ) / 0.7 )
P( Z = ( 3 - 5.1 ) / 1.5 )
P( Z = -3 ) = 0.0013
percent (%) of ancient prehistoric thinner than 3 is 0.0013
Try explaining how you worked the problem and how you did it
All the possible combinations are
1-1 2-1 3-1 4-1 5-1 6-1
1-2. 2-2 3-2 4-2. 5-2. 6-2
1-3 2-3. 3-3. 4-3. 5-3. 6-3
1-4. 2-4. 3-4. 4-4. 5-4. 6-4
1-5. 2-5. 3-5. 4-5. 5-5. 6-5
1-6. 2-6. 3-6. 4-6. 5-6. 6-6
What is the total for each roll?
2. 3. 4. 5. 6. 7.
3. 4. 5. 6. 7. 8
4. 5. 6. 7. 8. 9
5. 6. 7. 8. 9. 10.
6. 7. 8. 9. 10. 11.
7. 8. 9. 10. 11. 12
What roll occurs most often?
>>>>>>7<<<<<
7 occurs in 6 out of 36 possible outcomes
Answer:
x=2
Step-by-step explanation:
3x+17=14x-5 so...
22=11x (subtract 3x and add 5 to both sides)
2=x (divide both sides by 11)
Answer:
The records can be select in 332,640 ways.
Step-by-step explanation:
Consider the provided information.
There are 11 records to select from and a disc jokey can play 6 records.
Here, we need to find the number of permutation of n = 11 records taken r = 6 at a time.
Use the formula: 
Substitute the respective values in the above formula.
Hence, the records can be select in 332,640 ways.
