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yulyashka [42]
2 years ago
15

Who wants 100 points? Its free.

Mathematics
2 answers:
Zolol [24]2 years ago
6 0

Answer:

Baaa

Step-by-step explanation:

Heyyy

liberstina [14]2 years ago
5 0

Answer:me

Step-by-step explanation:

memememe

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What is the exact volume of the cylinder with a radius of 13 and a height of 30?
torisob [31]
The volume would be <span>15927.87
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</span>V ≈ 15927.87to be sure with my answer.
8 0
4 years ago
Find the interest earned in an account with $600 invested at 4.5% annual simple interest for 2 years.
astra-53 [7]

Answer:

40%

Step-by-step explanation:

every year the interested be 20%

that's why in 2 years be 40%interest

3 0
3 years ago
The demand for coffee is given by the following equation, where QD stands for the quantity demanded and P stands for price.
mart [117]

Using linear function concepts, it is found that the slopes and intercepts of the functions are given as follows:

a) -4.

b) P = 25.

c) 2.

d) P = 5.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

The demand is given by:

D = 100 - 4P.

Hence the slope is of -4. The demand is equals to zero when:

100 - 4P = 0 -> P = 25.

The supply is given by:

QS = -10 + 2P.

Hence the slope is of 2. The supply is equals to zero when:

-10 + 2P = 0 -> P = 5.

More can be learned about linear function concepts at brainly.com/question/24808124

#SPJ1

4 0
2 years ago
Pls help...................
bearhunter [10]
First one b ≤ 9 good luck
5 0
3 years ago
How to solve this linear equation step by step please
mote1985 [20]
\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ &#10;\begin{cases}&#10;c^2-4c=&c(c-4)\\&#10;2c^2+3c=&c(2c+3)\\\\&#10;2c^2-5c-12=&#10;&(2c+3)(c-4)&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\&#10;-------------------------------\\\\

\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}&#10;\\\\\\&#10;\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}&#10;\\\\\\&#10;\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}&#10;\\\\\\&#10;\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}&#10;\\\\\\&#10;-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c
7 0
3 years ago
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