Answer:
Clockwise rotation 90° about the center of (4,3)
Step-by-step explanation:
A, B, C: (1,6) (3,8) (5,6) -> A'B'C' (7,6) (9,4) (7,2)
clockwise 90° rotation formula:
x' = (y - y₀) + x₀ x: original x₀: center
y' = - (x - x₀) + y₀
For A (1,6) -> A' (7 , 6)
7 = (6 - y₀) + x₀ x₀ - y₀ = 1 ... (1)
6 = - (1 - x₀) + y₀ x₀ + y₀ = 7 ... (2)
(1) + (2): 2 x₀ = 8 x₀ = 4
(2)-(1): 2 y₀ = 6 y₀ = 3
Rotation center: (4 , 3)