3 years ago

What did you include in your response? Check all that apply.

Chemistry

1 answer:

klasskru [66]3 years ago

5 0

If you’re on edunity, check them all

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You have two solutions, both with a concentration of 0.1M. Solution A contains a weak acid with a pKa of 5. The pH of solution A

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Answer:guguhi

Explanation:

Guggugj

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If the 3.90 m solution from Part A boils at 103.45 âC, what is the actual value of the van't Hoff factor, i? The boiling point o

poizon [28]

Answer:

Van't Hoff factor is 1.72 ≅ 2

Explanation:

Let's apply the colligative property of boiling point elevation:

ΔT = Kb . m . i

ΔT = Boiling T° of solution - T° boiling of pure solvent

103.45 °C - 100°C = 0.512 °C/m . 3.90 m . i

3.45 °C / 0.512 m/°C . 3.90 m = i

1.72 = i ≅ 2

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Calculate the number of sulfate ions in 41.65 g of aluminum sulfate.

scoray [572]

The number of sulfate ions : 2.2 x 10²³

<h3>Further explanation</h3>

Reaction

Al₂(SO₄)₃⇒2Al³⁺+3SO₄²⁻

mol Al₂(SO₄)₃(MW=342,15 g/mol) :

$\tt \dfrac{41.65}{342.15}=0.122$

mol of sulfate ions (SO₄²⁻)

$\tt 3\times 0.122=0.366$

1 mol = 6.02 x 10²³ particles (ions, molecules, atoms), so for 0.366 mol :

$\tt 0.366\times 6.02\times 10^{23}=2.20\times 10^{23}$

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Which of the following will form a metallic bond with a metal?

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Which of the following is true regarding atomic radius?

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