Answer: a) 2H2 + O2 --> 2H2O
Explanation: 2 compounds are combining to form a new compound. The others have 2 substances as the end result and synthesis only produces one result (2H2O in this case)
<u>Answer:</u> The Gibbs free energy of the reaction is 21.32 kJ/mol
<u>Explanation:</u>
The chemical equation follows:

The equation used to Gibbs free energy of the reaction follows:

where,
= free energy of the reaction
= standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol (Conversion factor: 1 kJ = 1000 J)
R = Gas constant = 8.314J/K mol
T = Temperature = ![37^oC=[273+37]K=310K](https://tex.z-dn.net/?f=37%5EoC%3D%5B273%2B37%5DK%3D310K)
= Ratio of concentration of products and reactants = ![\frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5BOxaloacetate%5D%7D%5BNADH%5D%7D%7B%5Ctext%7B%5BMalate%5D%7D%5BNAD%5E%2B%5D%7D)
![\text{[Oxaloacetate]}=0.130mM](https://tex.z-dn.net/?f=%5Ctext%7B%5BOxaloacetate%5D%7D%3D0.130mM)
![[NADH]=2.0\times 10^2mM](https://tex.z-dn.net/?f=%5BNADH%5D%3D2.0%5Ctimes%2010%5E2mM)
![\text{[Malate]}=1.37mM](https://tex.z-dn.net/?f=%5Ctext%7B%5BMalate%5D%7D%3D1.37mM)
![[NAD^+]=490mM](https://tex.z-dn.net/?f=%5BNAD%5E%2B%5D%3D490mM)
Putting values in above expression, we get:

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol
Feet would be the best unit to use. Yards would work as well though.
Hope that helps!
The best definition of low electromagnetic energy would be A. Low electromagnetic energy has long wavelengths and low frequency.
Answer:
1. Percentage by weight = 0.5023 = 50.23 %
2. molar fraction =0.153
Explanation:
We know that
Molar mass of HClO4 = 100.46 g/mol
So the mass of 5 Moles= 5 x 100.46
Mass (m)= 5 x 100.46 = 502.3 g
Lets assume that aqueous solution of HClO4 and the density of solution is equal to density of water.
Given that concentration HClO4 is 5 M it means that it have 5 moles of HClO4 in 1000 ml.
We know that
Mass = density x volume
Mass of 1000 ml solution = 1 x 1000 =1000 ( density = 1 gm/ml)
m'=1000 g
1.
Percentage by weight = 502.3 /1000
Percentage by weight = 0.5023 = 50.23 %
2.
We know that
molar mass of water = 18 g/mol
mass of water in 1000 ml = 1000 - 502.3 g=497.9 g
So moles of water = 497.7 /18 mole
moles of water = 27.65 moles
So molar fraction = 5/(5+27.65)
molar fraction =0.153