All categories

3 years ago

My chosen word is quadratic form

Mathematics

1 answer:

sweet [91]3 years ago

6 0

Answer:

mine is creed for

Step-by-step explanation:

You might be interested in

In ΔEFG, the measure of ∠G=90°, EG = 11, FE = 61, and GF = 60. What ratio represents the sine of ∠F?

lapo4ka [179]

Answer:

sinF = $\frac{11}{61}$

Step-by-step explanation:

sinF = $\frac{opposite}{hypotenuse}$ = $\frac{EG}{FE}$ = $\frac{11}{61}$

6 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

Pls help!! and explain why the answer is correct !

pochemuha

Step-by-step explanation:

-3(2x-6)+4=-6x+18+4=-6x+22

7 0

3 years ago

Paul has two label-printing machines. Each machine can print 30 labels per minute. On day 1, only the first machine was used, an

Paraphin [41]

90+30x+30y. This is because the first day, 90 labels were printed, then you will use 30 times x to find how many minutes. This is the same for 30 times y. Youre trying to figure out how many minutes each machine printed for.

4 0

3 years ago

ASSAAAPPPP PLZ ANSWER THESE TWO QUESTIONS 33 POINTS

Keith_Richards [23]

Answer:

I can't see the questions please make bigger

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers