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3 years ago

What is the slope and y intercept I’m really new to this and need help

Mathematics

1 answer:

Troyanec [42]3 years ago

4 0

Answer:

The y intercept is -1 and the slope is 4/1

Step-by-step explanation:

When you are trying to find the y-intercept, you look at where the line crosses over the y axis. In this case it was at -1.

The slope indicates how many units it is going up/down or left/right. In this case, the distance between each point is up 4, and right 1. so the slope would be 4/1.

I hope this helps :)

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What is the measure of PRQ?

natima [27]

Answer:

the answer is 172

Step-by-step explanation:

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3 years ago

Read 2 more answers

A triangle had sides with lengths 5, 12, and 13.<br>verify this is a pythagorean triple

ra1l [238]

It is a pythagorean triple.

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2 years ago

In a parallel circuit, ET = 240 V, R = 330 Ω, and XL = 420 Ω. What is Z?

denis-greek [22]

Answer:

Z = 258Ω

Step-by-step explanation:

There are two methods of solving this question,

First method

Z = ( RXL)/ sqr rt ( R²+XL²)

Z= (330 Ω × 420 Ω)/ sqr rt ( 330 Ω² + 420 Ω²)

Z = 138600 Ω /534

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THE second complete method is given in attachment below

6 0

4 years ago

Rationalize the denominator and simplify.

cestrela7 [59]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3151018

——————————

$\mathsf{\dfrac{3\sqrt{6}+5\sqrt{2}}{4\sqrt{6}-3\sqrt{2}}}$

Multiply and divide by the conjugate of the denominator, which is $\mathsf{4\sqrt{6}+3\sqrt{2}:}$

$\mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot \big(4\sqrt{6}+3\sqrt{2}\big)}}$

Expand those products and eliminate the brackets:

$\mathsf{=\dfrac{\big(3\sqrt{6}+5\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(3\sqrt{6}+5\sqrt{2}\big)\cdot 3\sqrt{2}}{\big(4\sqrt{6}-3\sqrt{2}\big)\cdot 4\sqrt{6}+ \big(4\sqrt{6}-3\sqrt{2}\big)\cdot 3\sqrt{2}}}\\\\\\ \mathsf{=\dfrac{12\cdot \big(\sqrt{6}\big)^2+20\sqrt{2}\cdot \sqrt{6}+9\cdot \sqrt{6}\cdot \sqrt{2}+15\cdot \big(\sqrt{2}\big)^2}{16\cdot \big(\sqrt{6}\big)^2-12\cdot \sqrt{2}\cdot \sqrt{6}+ 12\cdot \sqrt{6}\cdot \sqrt{2}-9\cdot \big(\sqrt{2}\big)^2}}\\\\\\ \mathsf{=\dfrac{12\cdot 6+20\sqrt{2\cdot 6}+9\sqrt{6\cdot 2}+15\cdot 2}{16\cdot 6-12\sqrt{2\cdot 6}+ 12\sqrt{6\cdot 2}-9\cdot 2}}\\\\\\ \mathsf{=\dfrac{72+20\sqrt{12}+9\sqrt{12}+30}{96-12\sqrt{12}+12\sqrt{12}-18}}$

$\mathsf{=\dfrac{72+29\sqrt{12}+30}{96-18}}\\\\\\ \mathsf{=\dfrac{102+29\sqrt{2^2\cdot 3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot \sqrt{2^2}\cdot \sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{102+29\cdot 2\sqrt{3}}{78}}$

$\mathsf{=\dfrac{102+58\sqrt{3}}{78}}\\\\\\ \mathsf{=\dfrac{\,\diagup\!\!\!\! 2\cdot \big(51+29\sqrt{3}\big)}{\diagup\!\!\!\! 2\cdot 39}}$

$\mathsf{=\dfrac{51+29\sqrt{3}}{39}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

4 0

3 years ago

A map has a scale of 6 in. = 18 mi. If you measured the distance between two cities to be 26 in. on the map, how many miles woul

Travka [436]

Answer:

78 mi

Step-by-step explanation:

18/6 = 3

1 in= 3 mi

26×3= 78 mi

8 0

3 years ago