Sam is proving the product property of logarithms. Step justification mc030-1. Jpg given mc030-2. Jpg substitution which express
ion and justification completes the third step of her proof? mc030-3. Jpg; power rule of exponents mc030-4. Jpg subtraction property of exponents mc030-5. Jpg power rule of exponents mc030-6. Jpg division property of exponents.
The justification of the third step in her proof of the property of logarithms is; ; Power rule of exponents
<h3>What are properties of Logarithms?</h3>
From the full question, the second step stopped at;
Now, according to Power Rule for Exponents we know that (a^m)ⁿ = a^(m*n). That means that to raise a number with an exponent to a power, we will multiply the exponent times the power.
This is stating that, if x was 2, what is the answer to the equation. So basically, the equation is 2^2 - 2(2) = ? The first step is 2 squared, which is 4, then you subtract 2(2) or 4. So 4-4 is 0. The value of f(2) is 0 A would be correct.