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vazorg [7]
2 years ago
11

Transcribe DNA sequence GGTCAATGCCATAAG into mRNA

Biology
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

What does GGTCAATGCCATAAG into mRNA mean?

Explanation:

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Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some
Sphinxa [80]

Answer and Explanation:

<em><u>The number of observed individuals</u></em>:

  • AA 42
  • AG 24
  • GG 21

<u><em>Total number of individuals, N</em></u>= 87 = 42 + 24 + 21

<u><em>Allelic frequencies</em></u>:

  • f(p) = (2 x AA + AG)/ 2 x N

       f (p)= (2 x 42 + 24) /2 x 87

       f (p) = (84 + 24) / 174

       f (p)= 108 / 174

      f (p) = 0.62

  • f (q) = (2 x GG + AG)/2 x N

        f (q) = (2 x 21 + 24 )/2 x 87

        f (q) = (42 + 24)/ 174

        f (q) = 66/174

        f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

<em><u>The expected genotypic frequency:</u></em>

  • F (AA)= 0.62 ² = 0.3844
  • F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712
  • F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

<u><em>The number of expected individuals</em></u>:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

<u><em>Total number of expected individuals</em></u> = 33.44 + 40.99 + 12.563 = 87

<u><em>Chi square</em></u>= sum (O-E)²/E

  • AA= (O-E)² /E

        AA=(42 - 33.44) ² / 33.44

        AA= 2.2

  • AB= (O-E)² /E      

        AB= (24 - 40.99)²/ 40.99

        AB=7.04

  • BB=(O-E)² /E

        BB= (21-12.563)²/12.563

        BB= 5.66

<u><em>Chi square</em></u>= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

<u><em>Degrees of freedom</em></u> = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

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3 years ago
Which of the following shows the difference between aerobic and anaerobic respiration respiration?
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I think the correct answer is b sorry if wrong
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2 years ago
Describe the process of seed germination
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Basically the seed contains 2 parts, the testa, which is the seed coat that protects the seed and cotelydon, which is the inside of the seed, containing the radical and plumle.
for seed to germinate, we need 3 basic conditions,
warmth, it is the suitable temperature for seed germination, it can influence the activity of enzymes. providing a optimum temperature
water, to soften down the testa so that the shoot can break out from the testa
and oxygen, for aerobic respiration
.
If these conditions are absent, the seed may be in the state of dormancy. where is won't germinate until it meets the suitable conduction.
after that, the enzyme will digest the nutrient inside the seed and provide amino acid, which is necessary to seed germination. and meanwhile the aerobic respiration provides energy, so that the plumlecan shoot out, and be the shoot of the plant.
and then until it grows leaves, it'll start to complete photosynthesis, instead of using the nutrients inside the cotelydon.
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Science has nothing to do with
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Answer:

anything

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