A diploid cell resulting from the fusion of two haploid gametes
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
The answer is C, glacial till soil. Glacial till is a mixture of coarse clay and rock particles according to the reading.
The appropriate response is classical conditioning. It is a learning procedure that happens when two boosts are over and over combined; a reaction that is at first inspired by the second jolt is at the end evoked by the primary jolt alone. Classical conditioning is the essential learning procedure, and its neural substrates are presently starting to be caught on.
Answer:
B. increase, because the partial pressure of CO2 in the blood will decrease.
Explanation:
The presence of carbon dioxide gas in blood imparts H+ ions due to its reaction with H2O and thereby, lowers down the blood pH.
When more air reaches alveoli, the rate of gaseous exchange is increased. More of the carbon dioxide is removed from the blood and is released out of the body via exhalation.
Removal of carbon dioxide from blood would increase the pH of the blood since the partial pressure of CO2 in the blood would decrease.
