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3 years ago

5

Will give brainliest!Please find the area!

1 answer:

sveticcg [70]3 years ago

6 0

Answer:

70,000 brainliest meee

Step-by-step explanation:

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A printing company charges $42 plus $0.05 per page. Another company just charges $0.08 per page. How many pages are in an order

Nookie1986 [14]

There should be 1,400 pages in an order that costs the same for both companies.

Let x be the unknown number of pages.

1st Company = 42 + 0.05x
2nd Company = 0.08x

0.08x = 42 + 0.05x
0.08x - 0.05x = 42
0.03x = 42
0.03x / 0.03 = 42 / 0.03
x = 1400 pages

To check

0.08x = 42 + 0.05x
0.08 (1400) = 42 + (0.05 * 1400)
112 = 42 + 70
112 = 112

7 0

3 years ago

(I NEED THIS ANSWERED SUPER SUPER FAST PLEASE IT'S IMPORTANT!!!!!!)<br><br> 6 7/8c =__ fl oz

Olegator [25]

1 cup = 8 fluid ounces.
6.875 cups = ? fluid ounces.
8*6.875=55.

Your answer would be 55 fluid ounces.

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3 years ago

What do the following two equations represent?

alexira [117]

If you go on jiskha because you will find your answer by looking through search bar but the answe is B

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3 years ago

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15,000 feet to kilometers

KIM [24]

4.572 kilometers is the answer.

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3 years ago

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Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

So

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

So

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

3 years ago