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photoshop1234 [79]
3 years ago
8

HELPP plssss it’s important

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

3/2 is the slope

Step-by-step explanation:

find the negative inverse to give the perpendicular slope

本题已由中国数学会官方解答(现有会员:3人)

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Ashop has 3276 coat hangers. They store the coat hangers in boxes of 13. The shop also has 198 boxes of T-shirts. How many boxes
Dennis_Churaev [7]

Answer:

450 boxes

Step-by-step explanation:

3276÷13= 252

252+198=450. I hope this helps!*

8 0
3 years ago
A. The graph shows four points on the line and the triangles resulting from sketching on the rise and run from one point to the
Gnoma [55]

Answer:

A. Yes

B. The triangles are similar

C. The corresponding sides are proportional

D. The slope of ΔABC = tanθ₁ = tanθ₂ = The slope pf ΔDEF, therefore, the slope of any two points on the line are congruent by similar triangles

E. The rate of proportionality = 2

Step-by-step explanation:

A. From the given graph, given that the angles are formed between the transversal and lines parallel to the R-value axis and the transversal and lines parallel to the thickness axis, the angle formed by the transversal and each parallel lines are corresponding angles and are therefore congruent

The tan of one of the angles on each triangle are

On the uppermost triangle, tanθ₁ = (9.42 - 3.14)/(3 - 1) = 3.14

On the other triangle, tanθ₂ =(25.12 - 12.56)/(8 - 4) = 3.14

tanθ₁ = tanθ₂

∴ θ₁ = θ₂

ΔABC and ΔDEF are right triangles, therefore, all the angles of ΔABC and ΔDEF  are congruent

B. Given that the interior angles of the triangles formed by the line the graph are congruent, the triangles are similar by AA similarity postulate

C. Given that the triangles are similar, the length of the corresponding  sides of the triangles are proportional

D. Given that the slope is the tangent of the angle between the line of the graph and the Thickness axis, and that the angle is the same for both triangles, (∠θ₁ and ∠θ₂) the slope or the rise-to-run ratio is constant for the two triangles and also for any two points on the line

E. The Unit of proportionality is found using any two points as follows;

Using points used to show the proportional relationship on triangle ΔABC are (8, 25.12) and (4, 12.56) and on triangle ΔDEF, the two points used to show proportional relationship are (3, 9.42), and (1, 3.14)

The ratio of the corresponding sides on ΔABC and ΔDEF are

\overline {AC}/\overline {DF} = (25.12 - 12.56)/(9.42 - 3.14) = 2

\overline {BC}/\overline {EF} = (8 - 4)/(3 - 1) = 2

Therefore, the unit rate of proportionality which is the scale factor = 2.

3 0
3 years ago
The ratio of the length to the width of a map is 8 to 5. The map is exactly 32 inches in length. What is the width of the map? A
docker41 [41]
Ratio of length to width of a map = 8:5

Length of the map = 32 inches
Let the width of the map = x inches

So,

Length : Width = 8 : 5
32 : x= 8: 5

x = 5/8 * 32

x = 20 inches

So, the width of the map is 20 inches
8 0
3 years ago
Read 2 more answers
What is the area, in square centimeters, of the trapezoid below?<br> 8.5 cm<br> 7.5 cm<br> 15.7 cm
Contact [7]

Answer:

90.75 cm^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 ( b1+b2) *h

where b1 and b2 are the lengths of the bases and h is the height

A = 1/2(8.5+ 15.7) * 7.5

1/2 (24.2) 7.5

90.75 cm^2

6 0
2 years ago
Let f(x) = (x − 1)2, g(x) = e−2x, and h(x) = 1 + ln(1 − 2x). (a) Find the linearizations of f, g, and h at a = 0. What do you no
sweet [91]

Answer:

Lf(x) = Lg(x) = Lh(x) =  1 - 2x

value of the functions and their derivative are the same at x = 0

Step-by-step explanation:

Given :

f(x) = (x − 1)^2,  

g(x) = e^−2x ,  

h(x) = 1 + ln(1 − 2x).

a) Determine Linearization of  f, g and h  at a = 0

L(x) = f (a) + f'(a) (x-a)  ( linearization of <em>f</em> at <em>a</em> )

<u>for f(x) = (x − 1)^2   </u>

f'(x ) = 2( x - 1 )

at x = 0

f' = -2  

hence the Linearization at a = 0

Lf (x) = f(0) + f'(0) ( x - 0 )

Lf (x) = 1 -2 ( x - 0 ) = 1 - 2x

<u>For g(x) = e^−2x </u>

g'(x) = -2e^-2x

at x = 0

g(0) = 1

g'(0) = -2e^0 = -2

hence linearization at a = 0

Lg(x) = g ( 0 ) + g' (0) (x - 0 )

Lg(x) = 1 - 2x

<u>For h(x) = 1 + ln(1 − 2x).</u>

h'(x) =  -2 / ( 1 - 2x )

at x = 0

h(0) = 1

h'(0) = -2

hence linearization at a = 0

Lh(x) = h(0) + h'(0) (x-0)

        = 1 - 2x

<em>Observation and reason</em>

The Linearization is the same in every function i.e. Lf(x) = Lg(x) = Lh(x) this is because the value of the functions and their derivative are the same at x = 0

8 0
3 years ago
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